Run the ratio test on a power series and you get a radius R. That gives the open interval from c minus R to c plus R, where the series converges absolutely. Students frequently stop there, write an open interval, and lose the mark.
At each endpoint the ratio limit equals exactly 1, and the ratio test says nothing when L equals 1. Both endpoints have to be substituted back into the original series and tested by a different method. Four outcomes are possible, and all four occur in practice.
| Series | R | Left end | Right end | Interval |
|---|---|---|---|---|
| sum x^n | 1 | diverges | diverges | (-1, 1) |
| sum x^n / n | 1 | converges | diverges | [-1, 1) |
| sum x^n / n^2 | 1 | converges | converges | [-1, 1] |
| sum (-1)^n x^n / n | 1 | diverges | converges | (-1, 1] |
Study the second row. Radius 1, and the two endpoints disagree. Substituting x equal to 1 gives the harmonic series, which diverges. Substituting x equal to minus 1 gives the alternating harmonic series, which converges to negative log 2, about minus 0.693147. Identical radius, opposite verdicts, and the interval is half open because of it.